document.write( "Question 519838: please help me solve 5k^2+3k-2=0 by completing the square \n" ); document.write( "
Algebra.Com's Answer #345838 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! 5k^2 +3k -2 = 0 can be factored, so you do not need to complete the square. \n" ); document.write( "(5k-2)(k+1) = 0 \n" ); document.write( "so \n" ); document.write( "k = -1 or 2/5 \n" ); document.write( ". \n" ); document.write( "Check using FOIL \n" ); document.write( "5k^2 +5k -2k -2 = 5k^2 +3k -2 = 0 \n" ); document.write( ". \n" ); document.write( "Of course you can complete the square \n" ); document.write( "5k^2 +3k -2 = 0 \n" ); document.write( "Add 2 to both sides \n" ); document.write( "5k^2 +3k = 2 \n" ); document.write( "Divide through by coefficient of the squared term \n" ); document.write( "k^2 + 3/5k = 2/5 \n" ); document.write( "Take 1/2 of the coefficient of the 'k' term, square it and add to the left and right sides. \n" ); document.write( "1/2*3/5 = 3/10 \n" ); document.write( "(3/10)^2 = 9/100 \n" ); document.write( "k^2 + 3/5k + 9/100 = 2/5 + 9/100 \n" ); document.write( "(k + 3/10)^2 = 2/5 + 9/100 \n" ); document.write( "k + 3/10 = sqrt(2/5 + 9/100) \n" ); document.write( "k + 3/10 = sqrt(40/100 + 9/100) \n" ); document.write( "k + 3/10 = sqrt(49/100) \n" ); document.write( "k + 3/10 = +or- 7/10 \n" ); document.write( "so \n" ); document.write( "k = 7/10 -3/10 = 4/10 = 2/5 \n" ); document.write( "or \n" ); document.write( "k = -7/10 -3/10 = -10/10 = -1 \n" ); document.write( ". \n" ); document.write( "Same answer, either way. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " \n" ); document.write( " |