document.write( "Question 519758: A hospital staff mixed a 75% disinfectant solution with a 25% disinfectant solution. How many liters of each were used to make 10 L of a 40% disinfectant solution?
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Algebra.Com's Answer #345770 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
When doing mixture or solution problems, focus on how much 'pure' stuff you need.
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\n" ); document.write( "10 liters of 40% disinfectant will have 10*.4 = 4.0 liters of pure disinfectant and 6.0 liters of water (or some other solvent).
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\n" ); document.write( "x = liters of 75% solution to use
\n" ); document.write( "y = liters of 25% solution to use
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\n" ); document.write( "however, we know
\n" ); document.write( "x + y = 10
\n" ); document.write( "so
\n" ); document.write( "y = 10-x
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\n" ); document.write( "That approach means we have only one unknown and, therefore, only need one equation to solve it.
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\n" ); document.write( ".75*x + .25(10-x) = .40(10)
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\n" ); document.write( "multiply through by 100 to eliminate the decimals
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\n" ); document.write( "75x + 25(10-x) = 40(10)
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\n" ); document.write( "75x + 250 - 25x = 400
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\n" ); document.write( "50x = 150
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\n" ); document.write( "x = 3
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\n" ); document.write( "y = 10-3
\n" ); document.write( "y = 7
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\n" ); document.write( "Answer: Mix 3 liters of 75% disinfectant with 7 liters of 25% disinfectant to produce 10 liters of 40% solution.
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\n" ); document.write( "Check the answer by checking how much pure stuff you have.
\n" ); document.write( ".75*3 = 2.25
\n" ); document.write( ".25*7 = 1.75
\n" ); document.write( "2.25 + 1.75 = 4.00 liters of pure disinfectant in the 10 liters, which is a 40% solution.
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\n" ); document.write( "Done.
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