document.write( "Question 519758: A hospital staff mixed a 75% disinfectant solution with a 25% disinfectant solution. How many liters of each were used to make 10 L of a 40% disinfectant solution?
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document.write( "75% solution ? L
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document.write( "25% solution ? \n" );
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Algebra.Com's Answer #345770 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! When doing mixture or solution problems, focus on how much 'pure' stuff you need. \n" ); document.write( ". \n" ); document.write( "10 liters of 40% disinfectant will have 10*.4 = 4.0 liters of pure disinfectant and 6.0 liters of water (or some other solvent). \n" ); document.write( ". \n" ); document.write( "x = liters of 75% solution to use \n" ); document.write( "y = liters of 25% solution to use \n" ); document.write( ". \n" ); document.write( "however, we know \n" ); document.write( "x + y = 10 \n" ); document.write( "so \n" ); document.write( "y = 10-x \n" ); document.write( ". \n" ); document.write( "That approach means we have only one unknown and, therefore, only need one equation to solve it. \n" ); document.write( ". \n" ); document.write( ".75*x + .25(10-x) = .40(10) \n" ); document.write( ". \n" ); document.write( "multiply through by 100 to eliminate the decimals \n" ); document.write( ". \n" ); document.write( "75x + 25(10-x) = 40(10) \n" ); document.write( ". \n" ); document.write( "75x + 250 - 25x = 400 \n" ); document.write( ". \n" ); document.write( "50x = 150 \n" ); document.write( ". \n" ); document.write( "x = 3 \n" ); document.write( ". \n" ); document.write( "y = 10-3 \n" ); document.write( "y = 7 \n" ); document.write( ". \n" ); document.write( "Answer: Mix 3 liters of 75% disinfectant with 7 liters of 25% disinfectant to produce 10 liters of 40% solution. \n" ); document.write( ". \n" ); document.write( "Check the answer by checking how much pure stuff you have. \n" ); document.write( ".75*3 = 2.25 \n" ); document.write( ".25*7 = 1.75 \n" ); document.write( "2.25 + 1.75 = 4.00 liters of pure disinfectant in the 10 liters, which is a 40% solution. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |