document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519669>Question 519669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using substitution:<BR>\n" );
document.write( "3x+5y =-6    ;  x=5y+3\r<BR>\n" );
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document.write( "I have solved that Y= 3/4 but im not sure what to do with the fraction to figure x out. Thank You. Angela<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345723 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You should have gotten y = -3/4\r<BR>\n" );
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document.write( "Once you have y, you can use it to find x\r<BR>\n" );
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document.write( "x=5y+3 \r<BR>\n" );
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document.write( "x=5(-3/4)+3 \r<BR>\n" );
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document.write( "x=-15/4+3 \r<BR>\n" );
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document.write( "x=-15/4+12/4 \r<BR>\n" );
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document.write( "x=(-15+12)/4\r<BR>\n" );
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document.write( "x=-3/4\r<BR>\n" );
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document.write( "So the solutions are x = -3/4 and y = -3/4 </SPAN>\n" );
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