document.write( "Question 519623: Sharon and Rae are riding bicycles on the same trail in the same direction, shareon crosses a bridge at 12:18 pm, Rae crosses the same bridge at 12:33pm, If sharon is going 8mph and Rae is going 10mph, when will Rae catch up with sharon? \n" ); document.write( "
Algebra.Com's Answer #345714 by ankor@dixie-net.com(22740)\"\" \"About 
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Sharon and Rae are riding bicycles on the same trail in the same direction, shareon crosses a bridge at 12:18 pm, Rae crosses the same bridge at 12:33pm,
\n" ); document.write( " If sharon is going 8mph and Rae is going 10mph, when will Rae catch up with sharon?
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\n" ); document.write( "From the information given, we know that R is 15 min behind S, at 12:18 PM
\n" ); document.write( "convert 15 min to .25 hrs
\n" ); document.write( "Find the distance R is behind S at this time: .25(10) = 2.5 mi
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\n" ); document.write( "let t = time in hrs, that R catches s
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "10t = 8t + 2.5
\n" ); document.write( "10t - 8t = 2.5
\n" ); document.write( "2t = 2.5
\n" ); document.write( "t = 2.5/2
\n" ); document.write( "t = 1.25 hrs, which is 1 hr 15 min
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\n" ); document.write( "Find the time from 12:18 PM: 12:18 + 1:15 = 13:33, or 1:33 PM, R catches S
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\n" ); document.write( "Check this by finding the distance each rode
\n" ); document.write( "10*1.25 = 12.5 mi distance traveled
\n" ); document.write( "8*1.25 = 10 mi + 2.5 mi head start: = 12.5 \n" ); document.write( "
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