document.write( "Question 519455: The side of a square has length s. The length of a rectangle is 6 cm greater than the side of the square and the width of the rectangle is 3 cm less than the side of the square. The perimeter of the rectangle is 42 cm less than twice the perimeter of the square. Find the dimensions of each figure. \n" ); document.write( "
Algebra.Com's Answer #345624 by mananth(16946)![]() ![]() You can put this solution on YOUR website! square side = s\r \n" ); document.write( "\n" ); document.write( "rectangle length = s+6 \n" ); document.write( "rectangle width =s-3\r \n" ); document.write( "\n" ); document.write( "Perimeter of square = 4s \n" ); document.write( "Twice the perimeter = 8s \n" ); document.write( "perimeter of rectangle = 2*(s+6+s-3)=>2*(2s+3) \n" ); document.write( "=4s+6\r \n" ); document.write( "\n" ); document.write( "4s+6 = 8s-42\r \n" ); document.write( "\n" ); document.write( "4s-8s=-42-6 \n" ); document.write( "-4s=-48 \n" ); document.write( "/-4 \n" ); document.write( "s=12cm side of square \n" ); document.write( "... \n" ); document.write( "length of rectangle = s+6=>18cm \n" ); document.write( "width of rectangle = s-3=>9cm\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |