document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519447>Question 519447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An angle measures 15 more than its complement. Find the two angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345610 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = the angle<BR>\n" );
document.write( "90 - x = its complement {complementary angles add up to 90°}\r<BR>\n" );
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document.write( "x = 90 - x + 15 {an angle equals 15 more than its complement}<BR>\n" );
document.write( "x = 75 - x {combined like terms}<BR>\n" );
document.write( "2x = 75 {added x to both sides}<BR>\n" );
document.write( "x = 37.5 {divided both sides by 2}<BR>\n" );
document.write( "90 - x = 52.5 {substituted 37.5, in for x, into 90 - x}\r<BR>\n" );
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document.write( "37.5° and 52.5° are the two angles<BR>\n" );
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