document.write( "Question 51789: An auto service center has ten fifty-five gallon drums of 90% ethylene glycol, a common antifreeze fluid used in car radiators. The service center also has eight fifty-five gallon drums of 40% ethylene glycol solution as well. The manager wants to mix appropriate amounts of these two solutions to make 100 gallons of a 65% ethylene glycol concentration. How many gallons of the 90% solution will she need?\r
\n" ); document.write( "\n" ); document.write( "a. 10
\n" ); document.write( "b. 20
\n" ); document.write( "c. 30
\n" ); document.write( "d. 40
\n" ); document.write( "e. 50
\n" ); document.write( "f. 60
\n" ); document.write( "g. 70
\n" ); document.write( "h. 80
\n" ); document.write( "i. 90
\n" ); document.write( "j. none of these
\n" ); document.write( "

Algebra.Com's Answer #34561 by stanbon(75887)\"\" \"About 
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An auto service center has ten fifty-five gallon drums of 90% ethylene glycol, a common antifreeze fluid used in car radiators. The service center also has eight fifty-five gallon drums of 40% ethylene glycol solution as well. The manager wants to mix appropriate amounts of these two solutions to make 100 gallons of a 65% ethylene glycol concentration. How many gallons of the 90% solution will she need?
\n" ); document.write( "--------------
\n" ); document.write( "90% Fluid DATA:
\n" ); document.write( "Let amount of 90% fluid be \"x\"
\n" ); document.write( "Amount of active ingredient is 0.90x gallons.
\n" ); document.write( "40% Fluid DATA:
\n" ); document.write( "Amount of 40% fluid is \"100-x\" gallons.
\n" ); document.write( "Amount of active ingredient is 0.40(100-x)= 40-0.4x
\n" ); document.write( "Mixed Fluid DATA:
\n" ); document.write( "Amount is 100 gallons.
\n" ); document.write( "Amount of active ingredient is 0.65(100)= 65 gallons
\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.90x + 40-0.4x = 65
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "90x + 4000-40x=6500
\n" ); document.write( "50x = 1500
\n" ); document.write( "x=30 gallons of 90% fluid
\n" ); document.write( "100-x=70 gallons of 40% fluid
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
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