document.write( "Question 51789: An auto service center has ten fifty-five gallon drums of 90% ethylene glycol, a common antifreeze fluid used in car radiators. The service center also has eight fifty-five gallon drums of 40% ethylene glycol solution as well. The manager wants to mix appropriate amounts of these two solutions to make 100 gallons of a 65% ethylene glycol concentration. How many gallons of the 90% solution will she need?\r
\n" );
document.write( "\n" );
document.write( "a. 10
\n" );
document.write( "b. 20
\n" );
document.write( "c. 30
\n" );
document.write( "d. 40
\n" );
document.write( "e. 50
\n" );
document.write( "f. 60
\n" );
document.write( "g. 70
\n" );
document.write( "h. 80
\n" );
document.write( "i. 90
\n" );
document.write( "j. none of these \n" );
document.write( "
Algebra.Com's Answer #34561 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An auto service center has ten fifty-five gallon drums of 90% ethylene glycol, a common antifreeze fluid used in car radiators. The service center also has eight fifty-five gallon drums of 40% ethylene glycol solution as well. The manager wants to mix appropriate amounts of these two solutions to make 100 gallons of a 65% ethylene glycol concentration. How many gallons of the 90% solution will she need? \n" ); document.write( "-------------- \n" ); document.write( "90% Fluid DATA: \n" ); document.write( "Let amount of 90% fluid be \"x\" \n" ); document.write( "Amount of active ingredient is 0.90x gallons. \n" ); document.write( "40% Fluid DATA: \n" ); document.write( "Amount of 40% fluid is \"100-x\" gallons. \n" ); document.write( "Amount of active ingredient is 0.40(100-x)= 40-0.4x \n" ); document.write( "Mixed Fluid DATA: \n" ); document.write( "Amount is 100 gallons. \n" ); document.write( "Amount of active ingredient is 0.65(100)= 65 gallons \n" ); document.write( "EQUATION: \n" ); document.write( "active + active = active \n" ); document.write( "0.90x + 40-0.4x = 65 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "90x + 4000-40x=6500 \n" ); document.write( "50x = 1500 \n" ); document.write( "x=30 gallons of 90% fluid \n" ); document.write( "100-x=70 gallons of 40% fluid \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |