document.write( "Question 519343: Please help me multiply this expression. (3x+3y)^2(2x+3y). I did the () first and got (9x^2+9y^2)(2x+3y). If I use the FOIL method then there are mixed variables. My confusion is now what do I do? \n" ); document.write( "
Algebra.Com's Answer #345584 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! (3x+3y)^2*(2x+3y) \n" ); document.write( "First FOIL \n" ); document.write( "(3x + 3y)* (3x + 3y) = 9x^2 + 9xy + 9xy + 9y^2 \n" ); document.write( "Combine like terms and you have \n" ); document.write( "9x^2 + 18xy + 9y^2 \n" ); document.write( ": \n" ); document.write( "Multiply this by (2x+3y), but do it this way, long multiplication \n" ); document.write( "9x^2 + 18xy + 9y^2 \n" ); document.write( ". . . . . . . . . 2x + 3y \n" ); document.write( "------------------ \n" ); document.write( ": \n" ); document.write( "You should get: 18x^3 + 63x^y + 72xy^2 + 27y^3 \n" ); document.write( "Corrected to: 18x^3 \n" ); document.write( " \n" ); document.write( " |