document.write( "Question 518948: Pat has $3.80 in nickels and dimes. If there are 51 coins in all, how many of them are nickels
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Algebra.Com's Answer #345523 by ankor@dixie-net.com(22740)\"\" \"About 
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Pat has $3.80 in nickels and dimes.
\n" ); document.write( "Let's do this equation in cents
\n" ); document.write( "5n + 10d = 380
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\n" ); document.write( " If there are 51 coins in all,
\n" ); document.write( "n + d = 51
\n" ); document.write( "Multiply by 10, subtract the 1st equation
\n" ); document.write( "10n + 10d = 510
\n" ); document.write( " 5n + 10d = 380
\n" ); document.write( "----------------Subtraction eliminates d, find n;
\n" ); document.write( "5n = 130
\n" ); document.write( "n = 130/5
\n" ); document.write( "n = 26 nickels
\n" ); document.write( "then
\n" ); document.write( "51 - 26 = 25 dimes
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\n" ); document.write( "Check solutions by finding the actual value:
\n" ); document.write( ".05(26) + .10(25) =
\n" ); document.write( "1.30 + 2.50 = 3.80 \n" ); document.write( "
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