document.write( "Question 518948: Pat has $3.80 in nickels and dimes. If there are 51 coins in all, how many of them are nickels
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Algebra.Com's Answer #345519 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Nickels = x
\n" ); document.write( "Dimes = 51-x
\n" ); document.write( "Total Amount = $3.80 = 3.80*100=380 cents\r
\n" ); document.write( "\n" ); document.write( "5x+10(51-x)=380
\n" ); document.write( "5x+510-10x=380
\n" ); document.write( "5x-10x=380-510
\n" ); document.write( "-5x=-130
\n" ); document.write( "-5x/-5=-130/-5
\n" ); document.write( "x=26\r
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\n" ); document.write( "\n" ); document.write( "Nickels = x = 26
\n" ); document.write( "Dimes = 51-x = 51-26 = 25\r
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\n" ); document.write( "5*26 + 10*25 = 380
\n" ); document.write( "130+250=380
\n" ); document.write( "380=380\r
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