document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519290>Question 519290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the standard form of the equation through the points (4,2) and perpendicular to y=2x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345507 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Standard Form of Equation of the line:<BR>\n" );
document.write( "y=mx+b<BR>\n" );
document.write( "Given<BR>\n" );
document.write( "y=2x-1<BR>\n" );
document.write( "Compare above equation with the standard form equation<BR>\n" );
document.write( "m=2 and b=-1<BR>\n" );
document.write( "Since lines are perpendicular multiplicatin of their slope will be (-1)<BR>\n" );
document.write( "So slope of the required line will be (-1/2)<BR>\n" );
document.write( "Now we have a point(4,2) and slope (-1/2)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.<BR>\n" );
document.write( "m=(y2-y1)/(x2-x1)<BR>\n" );
document.write( "-1/2=(y-2))/(x-4)<BR>\n" );
document.write( "-(x-4)=2(y-2)<BR>\n" );
document.write( "-x+4=2y-4<BR>\n" );
document.write( "-2y=x-4-4<BR>\n" );
document.write( "-2y=x-8<BR>\n" );
document.write( "-2y/-2=(x-8)/-2<BR>\n" );
document.write( "y=-x/2+8/2<BR>\n" );
document.write( "y=-x/2+4<BR>\n" );
document.write( "Above equation is the standard form of the equation of the line<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );