document.write( "Question 519281: 2/3 + X/5<4/15 SOLVE USING ADDITION AND MULTIPLICATION PRINCIPALS\r
\n" ); document.write( "\n" ); document.write( "HERE IS WHAT I HAVE SO FAR:\r
\n" ); document.write( "\n" ); document.write( "X/5 + 2/3 <4/15\r
\n" ); document.write( "\n" ); document.write( "2*X/3.5 <4/15 =
\n" ); document.write( "2*X/15 < 4/15 \r
\n" ); document.write( "\n" ); document.write( "AM I DONE OR IS THERE MORE?
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Algebra.Com's Answer #345495 by Edwin McCravy(20055) $\"\"$ $\"About$

You can put this solution on YOUR website!
2/3 + X/5 < 4/15 SOLVE USING ADDITION AND MULTIPLICATION PRINCIPALS\r
\n" ); document.write( "\n" ); document.write( "HERE IS WHAT I HAVE SO FAR:\r
\n" ); document.write( "\n" ); document.write( "X/5 + 2/3 < 4/15\r
\n" ); document.write( "\n" ); document.write( "2*X/3.5 < 4/15 =
\n" ); document.write( "2*X/15 < 4/15 \r
\n" ); document.write( "\n" ); document.write( "AM I DONE OR IS THERE MORE?
\n" ); document.write( "

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document.write( "Sorry, that's all wrong.  Here's what you do:\r\n" );
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document.write( "        +  < \r\n" );
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document.write( "Multiply every term by LCD = 15\r\n" );
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document.write( " 15· + 15· < 15·\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( "      3X + 10 < 4\r\n" );
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document.write( "Add -10 to both sides:\r\n" );
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document.write( "           3X < 4-10\r\n" );
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document.write( "           3X < -6\r\n" );
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document.write( "Divide both sides by 3\r\n" );
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document.write( "            < \r\n" );
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document.write( "              X < -2\r\n" );
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document.write( "[As long as you divide or multiply only by positive\r\n" );
document.write( "numbers, you don't flip the inequality sign].\r\n" );
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document.write( "Edwin

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