document.write( "Question 519277: I have a cup full of change (nickels and quarters).
\n" ); document.write( "* The value of the coins is $28.95.
\n" ); document.write( "* There are a total of 187 coins.\r
\n" ); document.write( "\n" ); document.write( "How many of each coin do I have? \n" ); document.write( "

Algebra.Com's Answer #345489 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
nickels x coins
\n" ); document.write( "quarters y coins
\n" ); document.write( "
\n" ); document.write( "1 x + 1 y = 187 .............1
\n" ); document.write( "5 x + 25 y = 2895 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -25
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-25 x -25 y = -4675
\n" ); document.write( "5 x 25 y = 2895
\n" ); document.write( "Add the two equations
\n" ); document.write( "-20 x = -1780
\n" ); document.write( "/ -20
\n" ); document.write( "x = 89
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 187
\n" ); document.write( "89 + 1 y = 187
\n" ); document.write( " 1 y = 187 -89
\n" ); document.write( " 1 y = 98
\n" ); document.write( " y = 98\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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