document.write( "Question 519270: the solution to a system of two linear equations is (4,-3). one equation has a slope of 4. the slope of the other line is the negative recipical of the slope of the first. find the system of equations \n" ); document.write( "
Algebra.Com's Answer #345488 by mananth(16946)\"\" \"About 
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(4,-3) slope = 4\r
\n" ); document.write( "\n" ); document.write( "m= 4
\n" ); document.write( "
\n" ); document.write( "Plug value of the slope and point ( 4 , -3 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "-3.00 = 16 + b
\n" ); document.write( "b= -3 - 16
\n" ); document.write( "b= -19
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = 4 x -19
\n" ); document.write( "-4x+y=-19............................1
\n" ); document.write( "-----
\n" ); document.write( "(4,-3) slope = -1/4\r
\n" ); document.write( "\n" ); document.write( "m= - 1/ 4
\n" ); document.write( "
\n" ); document.write( "Plug value of the slope and point ( 4 , -3 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "-3.00 = -1 + b
\n" ); document.write( "b= -3 - -1
\n" ); document.write( "b= -2
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = - 1/4 x -2
\n" ); document.write( "4y=-x-8
\n" ); document.write( "4y+x=-8 ........................2 \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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