document.write( "Question 519251: A man is 3 times as old as his son. 8 years ago the product of their age was 112. Find their ages \n" ); document.write( "
Algebra.Com's Answer #345466 by mananth(16946)\"\" \"About 
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son = x
\n" ); document.write( "father = 3x\r
\n" ); document.write( "\n" ); document.write( "8 years ago\r
\n" ); document.write( "\n" ); document.write( "son = x-8
\n" ); document.write( "father = 3x-8\r
\n" ); document.write( "\n" ); document.write( "(x-8)(3x-8)=112\r
\n" ); document.write( "\n" ); document.write( "3x^2-32x+64=112
\n" ); document.write( "3x^2-32x-48=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 3 ,b= -32 ,c= -48
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 1024 + 576
\n" ); document.write( "b^2-4ac= 1600
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-12%2B21%29%2F%2812%29\"
\n" ); document.write( "x1=( 32 + 40 )/ 6
\n" ); document.write( "x1= 12
\n" ); document.write( "x2=( 32 -40 ) / 6
\n" ); document.write( "x2= -1.33
\n" ); document.write( "Ignore negative value \r
\n" ); document.write( "\n" ); document.write( "son = 12 yaers
\n" ); document.write( "father = 36 years\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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