document.write( "Question 519251: A man is 3 times as old as his son. 8 years ago the product of their age was 112. Find their ages \n" ); document.write( "
Algebra.Com's Answer #345466 by mananth(16946)![]() ![]() You can put this solution on YOUR website! son = x \n" ); document.write( "father = 3x\r \n" ); document.write( "\n" ); document.write( "8 years ago\r \n" ); document.write( "\n" ); document.write( "son = x-8 \n" ); document.write( "father = 3x-8\r \n" ); document.write( "\n" ); document.write( "(x-8)(3x-8)=112\r \n" ); document.write( "\n" ); document.write( "3x^2-32x+64=112 \n" ); document.write( "3x^2-32x-48=0 \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 3 ,b= -32 ,c= -48 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 1024 + 576 \n" ); document.write( "b^2-4ac= 1600 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 32 + 40 )/ 6 \n" ); document.write( "x1= 12 \n" ); document.write( "x2=( 32 -40 ) / 6 \n" ); document.write( "x2= -1.33 \n" ); document.write( "Ignore negative value \r \n" ); document.write( "\n" ); document.write( "son = 12 yaers \n" ); document.write( "father = 36 years\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |