document.write( "Question 519208: there are 10 pints of a 40% acid solution that is being added to 4 pints of an 80% solution. what will be the level of acid concentration in the mixture? \n" ); document.write( "
Algebra.Com's Answer #345444 by stanbon(75887)\"\" \"About 
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there are 10 pints of a 40% acid solution that is being added to 4 pints of an 80% solution. what will be the level of acid concentration in the mixture?
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.40*10 + 0.80*4 = x*(14)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40*10 + 80*4 = 1400x
\n" ); document.write( "40 + 320 = 1400x
\n" ); document.write( "x = 360/1400
\n" ); document.write( "x = 0.257 = 25.7%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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