document.write( "Question 519208: there are 10 pints of a 40% acid solution that is being added to 4 pints of an 80% solution. what will be the level of acid concentration in the mixture? \n" ); document.write( "
Algebra.Com's Answer #345444 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! there are 10 pints of a 40% acid solution that is being added to 4 pints of an 80% solution. what will be the level of acid concentration in the mixture? \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.40*10 + 0.80*4 = x*(14) \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40*10 + 80*4 = 1400x \n" ); document.write( "40 + 320 = 1400x \n" ); document.write( "x = 360/1400 \n" ); document.write( "x = 0.257 = 25.7% \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================= \n" ); document.write( " |