document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519158>Question 519158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Systems of linear equations by substitution\r<BR>\n" );
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document.write( "2x-5y=10<BR>\n" );
document.write( "y=2/5x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345422 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is not a system of equations.<BR>\n" );
document.write( "This is one equation in two forms.<BR>\n" );
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document.write( "2x -5y = 10<BR>\n" );
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document.write( "Subtract 2x from both sides<BR>\n" );
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document.write( "-5y = -2x +10<BR>\n" );
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document.write( "Divide both sides by -5<BR>\n" );
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document.write( "y = 2/5x -2<BR>\n" );
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document.write( "If you want to consider these as two equations, then they line on top of one another.<BR>\n" );
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