document.write( "Question 519069: One of the digits of a two digit number is 6, whose sum is half of their
\n" ); document.write( "product, and whose product is half of the reverse order number. What is
\n" ); document.write( "the number?
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Algebra.Com's Answer #345418 by mamiya(56)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let xy be the number, where x is the first digit and y the second one.
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\n" ); document.write( " based on the question, x+y=x*y/2 and x*y=yx/2 ( yx represents a number not a product)\r
\n" ); document.write( "\n" ); document.write( "so we have, x+y=x*y/2
\n" ); document.write( " x*y= (10y+x)/2 \r
\n" ); document.write( "\n" ); document.write( " 2(x + y)= x*y
\n" ); document.write( " x*y= (10y+x)/2
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\n" ); document.write( " so, 2(x+y)=(10y+x)/2
\n" ); document.write( " 2*2(x+y)=2(10y+x)/2
\n" ); document.write( " 4(x+y)=10y+x
\n" ); document.write( " 3x=6y
\n" ); document.write( " x=2y
\n" ); document.write( " we know that x and y are integer numbers because they are digits of a number.
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\n" ); document.write( " the question says, one of the digit is 6 but we let's say y is the one who is 6
\n" ); document.write( " if y=6, we would have, x=2*6=12, and this would make any sense since x is supposed to be a digit not a number, so y is not 6. since y is not 6, we can affirm the digit that is 6 is x.\r
\n" ); document.write( "\n" ); document.write( " so x=6 , y=x/2=6/2=3.\r
\n" ); document.write( "\n" ); document.write( "so xy=63. \r
\n" ); document.write( "\n" ); document.write( "the answer is 63.\r
\n" ); document.write( "\n" ); document.write( "we can check our answer.
\n" ); document.write( "6+3=(6*3)/2 and 6*3=36/2
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