document.write( "Question 519146: An express and local train leave GraysLake at 3 P.M. and head for Chicago 55 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #345417 by nerdybill(7384)\"\" \"About 
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An express and local train leave GraysLake at 3 P.M. and head for Chicago 55 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
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\n" ); document.write( "Let x = speed of local
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\n" ); document.write( "2x = speed of express
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\n" ); document.write( "Let t = time traveled by local
\n" ); document.write( "then
\n" ); document.write( "t-1 = time traveled by express
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\n" ); document.write( "Applying distance formula:
\n" ); document.write( "since the distance traveled is the same:
\n" ); document.write( "xt = 2x(t-1)
\n" ); document.write( "dividing both sides by x:
\n" ); document.write( "t = 2(t-1)
\n" ); document.write( "t = 2t-2
\n" ); document.write( "2 hours = t (time traveled by local)
\n" ); document.write( "speed of local:
\n" ); document.write( "55/2 = 27.5 mph
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\n" ); document.write( "time traveled by express:
\n" ); document.write( "t-1 = 2-1 = 1 hour
\n" ); document.write( "speed of express:
\n" ); document.write( "55/1 = 55 mph\r
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