document.write( "Question 518919: Pls help me solve this question\r
\n" ); document.write( "\n" ); document.write( "A and B play the following game.They throw alternatively a pair of dice.Whosoever gets sum of two numbers on the top as 7 wins the game and the game stops.Suppose A starts the game,find the probability that\r
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Algebra.Com's Answer #345415 by richard1234(7193)\"\" \"About 
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The probability of getting a 7 on two dice is 1/6.\r
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\n" ); document.write( "\n" ); document.write( "The probability that A wins right away is 1/6. Hence, the probability that B wins right away is (5/6)(1/6) = 5/36. \r
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\n" ); document.write( "\n" ); document.write( "The probability that A wins on his second throw is (5/6)(5/6)(1/6) = 25/216. Hence, the probability that B wins on his second throw is (5/6)(5/6)(5/6)(1/6) = 125/1296.\r
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\n" ); document.write( "\n" ); document.write( "We repeat this pattern to obtain\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the probability that A wins is 6/11, and the probability that B wins is 1 - (6/11), or 5/11.
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