document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519114>Question 519114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For what values in the interval 0<x<180 is<BR>\n" );
document.write( " 2-4 sin 2x < 0? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345406 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For what values in the interval 0<180 is<BR>\n" );
document.write( "2-4 sin 2x < 0<BR>\n" );
document.write( "**<BR>\n" );
document.write( "2-4 sin 2x < 0<BR>\n" );
document.write( "-4sin 2x<-2<BR>\n" );
document.write( "divide by -4 and reverse inequality sign<BR>\n" );
document.write( "sin 2x>-2/-4=1/2<BR>\n" );
document.write( "2x>30º<BR>\n" );
document.write( "x>30/2=15º<BR>\n" );
document.write( "The interval 0-180 are quadrants I and II where sin>0<BR>\n" );
document.write( "Solutions:180º>x>15º and 180º>x>165º </SPAN>\n" );
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