document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519131>Question 519131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two times the complement of an angle is 27 more than the angle. find the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345400 by </B><A HREF=/tutors/aboutme.mpl?userid=mamiya><B>mamiya(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mamiya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two times the complement of an angle is 27 more than the angle. find the angle.\r<BR>\n" );
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document.write( "let's x be the angle. its complement of x is 90-x, since two angles are complementary if their sum equal 90<BR>\n" );
document.write( " two times the complement of x is 2( 90-x)<BR>\n" );
document.write( " 2(90-x) is 27 more than x, means that 2(90-x)=x+27<BR>\n" );
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document.write( "so, 180-2x=x+27<BR>\n" );
document.write( "    180-27=2x+x<BR>\n" );
document.write( "    3x=153<BR>\n" );
document.write( "     x=51\r<BR>\n" );
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document.write( "so, the answer is 51 degree </SPAN>\n" );
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