document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519106>Question 519106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first.\r<BR>\n" );
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document.write( "cos^2 x- sin^2 x = sqr3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345380 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write the general solution first. <BR>\n" );
document.write( "cos^2 x- sin^2 x = sqr3/2<BR>\n" );
document.write( "**<BR>\n" );
document.write( "cos^2x-sin^2x=&#8730;3/2<BR>\n" );
document.write( "1-sin^2x-sin^2x=&#8730;3/2<BR>\n" );
document.write( "1-sin^2x-(1-cos^2x)=&#8730;3/2<BR>\n" );
document.write( "1-sin^2x-1+cos^2x=&#8730;3/2<BR>\n" );
document.write( "cos^2x-sin^2x=&#8730;3/2<BR>\n" );
document.write( "cos(2x)=&#8730;3/2<BR>\n" );
document.write( "2x=&#960;/6<BR>\n" );
document.write( "x=&#960;/12 </SPAN>\n" );
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