document.write( "Question 518946: A stationary cyclist is passed by another cyclist riding with a constant speed of 3.4 m/s. Immediately as the other bike passes the stationary bicyclist hops on his bike and accelerates at 2.4m/s2 until he catches up. (a) How much time does it take to catch up and how far has he travelled in this time? \n" ); document.write( "
Algebra.Com's Answer #345366 by ankor@dixie-net.com(22740)\"\" \"About 
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A stationary cyclist is passed by another cyclist riding with a constant speed of 3.4 m/s.
\n" ); document.write( " Immediately as the other bike passes the stationary bicyclist hops on his bike and accelerates at 2.4m/s2 until he catches up.
\n" ); document.write( " (a) How much time does it take to catch up and how far has he traveled in this time?
\n" ); document.write( ":
\n" ); document.write( "Let t = time required for him to catch up
\n" ); document.write( "then
\n" ); document.write( "3.4t = distance (in meters) traveled by both bikes when this happens
\n" ); document.write( ":
\n" ); document.write( "2.4t = cyclist speed after t seconds
\n" ); document.write( "\"2.4t%2F2\" = av velocity of cyclist over this distance, (from 0 to 2.4t m/s^2)
\n" ); document.write( ":
\n" ); document.write( "\"2.4t%2F2\"*t =\"%282.4t%5E2%29%2F2\" = 1.2t^2 distance traveled over t time
\n" ); document.write( "It is equal to the other rider's dist
\n" ); document.write( "1.2t^2 = 3.4t
\n" ); document.write( "1.2t^2 - 3.4t = 0
\n" ); document.write( "Divide both sides by 1.2t
\n" ); document.write( "1.2t(t - 2.83) = 0
\n" ); document.write( "t = 0, start time
\n" ); document.write( "and
\n" ); document.write( "t = 2.83 seconds to catch up
\n" ); document.write( "dist = 2.83 * 3.4 = 9.622 meters
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