document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=519041>Question 519041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three time the complement of angle A is 60 degrees less then the supplement of angle A. find teh measure of angle A. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345362 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = measure of angle A<BR>\n" );
document.write( "90 - x = complement of angle A {complementary angles add up to 90°}<BR>\n" );
document.write( "180 - x = supplement of angle A {supplementary angles add up to 180°}\r<BR>\n" );
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document.write( "3(90 - x) = 180 - x - 60 {three times complement is 60 less than supplement}<BR>\n" );
document.write( "270 - 3x = 120 - x {used distributive property on left, combined like terms on right}<BR>\n" );
document.write( "150 - 3x = -x {subtracted 120 from both sides}<BR>\n" );
document.write( "150 = 2x {added 3x to both sides}<BR>\n" );
document.write( "x = 75 {divided both sides by 2}\r<BR>\n" );
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document.write( "angle A = 75°<BR>\n" );
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