document.write( "Question 518949: A doctor squirts a small amount of liquid from a syringe vertically. If the liquid emerges with a velocity of 5.5 m/s how long does it take for the liquid to return to the level of the syringe and what is the maximum height it can reach? \n" ); document.write( "
Algebra.Com's Answer #345346 by Earlsdon(6294)\"\" \"About 
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Use the function:
\n" ); document.write( "\"h%28t%29+=+-4.9t%5E2%2Bv%5B0%5Dt%2Bh%5B0%5D\"
\n" ); document.write( "This is the function for determining the height (in meters) of an object (liquid in this case) propelled upwards with an initial velocity \"v%5B0%5D\"(in meters per second) from an initial height of \"h%5B0%5D\" (in meters) at time t (in seconds).
\n" ); document.write( "\"h%28t%29+=+-4.9t%5E2%2Bv%5B0%5Dt%2Bh%5B0%5D\" Substitute \"v%5B0%5D+=+5.5\", \"h%5B0%5D+=+0\" and \"h%28t%29+=+0\" to find the time, t, at which the liquid will return to its initial height.
\n" ); document.write( "\"0+=+-4.9t%5E2%2B5.5t\" Factor a t.
\n" ); document.write( "\"t%28-4.9t%2B5.5%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"t+=+0\" This is the initial state.
\n" ); document.write( "\"-4.9t%2B5.5+=+0\" Solve for t.
\n" ); document.write( "\"4.9t+=+5.5\"
\n" ); document.write( "\"t+=+1.12\" seconds to return to its initial height at the doctor's syringe.
\n" ); document.write( "To find the maximum height of the object (liquid), you need to find the vertex of the parabola which is the graph of the equation:
\n" ); document.write( "\"h%28t%29+=+-4.9t%5E2%2B5.5t\" This graphs into a parabola that opens downward so its vertex will be the maximum height.
\n" ); document.write( "\"h%28t%29+=+-4.9t%5E2%2B5.5t\" The value of t at the vertex is given by:
\n" ); document.write( "\"t+=+-b%2F2a\" where b = 5.5 and a = -4.9
\n" ); document.write( "\"t+=+%28-5.5%29%2F2%28-4.9%29\"
\n" ); document.write( "\"t+=+0.56\" seconds. This is the time at which the object reaches its maximum height. Substitute this into the function for the height to find the maximum height in meters.
\n" ); document.write( "\"h%280.56%29+=+-4.9%280.56%29%5E2%2B5.5%280.56%29\"
\n" ); document.write( "\"h%280.56%29+=+1.54\" meters.
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