document.write( "Question 519008: Find the equation of the line using the given information and in the requested form.\r
\n" ); document.write( "\n" ); document.write( "1.Perpendicular to 7x-2y=-2 and passing through the point (7,1); in slope-intercept form.\r
\n" ); document.write( "\n" ); document.write( "2.Parallel to 3y-4x=3 and passing through the point (0,5); in slope-intercept form.
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Algebra.Com's Answer #345342 by Maths68(1474)\"\" \"About 
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1.Perpendicular to 7x-2y=-2 and passing through the point (7,1); in slope-intercept form.\r
\n" ); document.write( "\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "7x-2y=-2
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "-2y=-7x-2
\n" ); document.write( "-2y/-2=(-7x-2)/-2
\n" ); document.write( "y=(7/2)x+1
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=7/2 and b=1
\n" ); document.write( "Since lines are perpendicular multiplicatin of their slope will be (-1)
\n" ); document.write( "So slope of the required line will be (-2/7)
\n" ); document.write( "Now we have a point(7,1) and slope (-2/7)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "-2/7=(y-1))/(x-7)
\n" ); document.write( "-2(x-7)=7(y-1))
\n" ); document.write( "-2x+14=7y-7
\n" ); document.write( "-2x-7y=-7-14
\n" ); document.write( "-2x-7y=-21
\n" ); document.write( "Multiply by -1 both sides of the equation
\n" ); document.write( "2x+7y=21
\n" ); document.write( "7y=-2x+21
\n" ); document.write( "7y/7=(-2x+21)/7
\n" ); document.write( "y=(-2/7)x+3
\n" ); document.write( "Above equation is slope intercept form of the equation of the required line\r
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\n" ); document.write( "\n" ); document.write( "2.Parallel to 3y-4x=3 and passing through the point (0,5); in slope-intercept form.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given
\n" ); document.write( "3y-4x=3
\n" ); document.write( "rearrage the above equation according to the standard form
\n" ); document.write( "3y-4x=3
\n" ); document.write( "3y=4x+3
\n" ); document.write( "3y/3=(4x+3)/3
\n" ); document.write( "y=4/3(x)+1
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "m=4/3 and b=1
\n" ); document.write( "Since lines are parallel their slopes will be same.
\n" ); document.write( "So slope of the required line will be (4/3)
\n" ); document.write( "Now we have a point(0,5) and slope (4/3)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "4/3=(y-5))/(x-0)
\n" ); document.write( "4(x-0)=3(y-5)
\n" ); document.write( "4x=3y-15
\n" ); document.write( "-3y=-4x-15
\n" ); document.write( "-3y/-3=(-4x-15)/-3
\n" ); document.write( "y=(4/3)x+5
\n" ); document.write( "Above equation is slope intercept form of the equation of the required line \n" ); document.write( "
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