document.write( "Question 518993: 4. A nursing station in a large hospital has determined that the average amount of time applied to each patient on their floor has been about 36 minutes a day with a standard deviation of 12 minutes. \r
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document.write( "a. What is the probability that a random sample of 49 patients would average less than 33 minutes of attention or care?\r
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document.write( "b. This nursing station knows that whenever the average time of care exceeds 42 minutes, they need to add another nurse. What is the likelihood of this?
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Algebra.Com's Answer #345324 by stanbon(75887) ![]() You can put this solution on YOUR website! A nursing station in a large hospital has determined that the average amount of time applied to each patient on their floor has been about 36 minutes a day with a standard deviation of 12 minutes. \n" ); document.write( "91---------------- \n" ); document.write( "a. What is the probability that a random sample of 49 patients would average less than 33 minutes of attention or care? \n" ); document.write( "z(33) = (33-36)/[12/sqrt(49)] = =1.75 \n" ); document.write( "P(x-bar < 33) = P(z < -1.75) = 0.0401 \n" ); document.write( "---------------------------------------------- \n" ); document.write( "b. This nursing station knows that whenever the average time of care exceeds 42 minutes, they need to add another nurse. What is the likelihood of this? \n" ); document.write( "z(42) = (42-36)/12 = 1/2 \n" ); document.write( "P(x > 42) = P(z > 1/2) = 0.3085 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |