document.write( "Question 518892: Interest in the amount of $1785 is earned in accounts bearing 6.5% and 7.5% simple interest. If the total amount invested was %25,000, how much was invested in the account bearing 6.5%? \n" ); document.write( "
Algebra.Com's Answer #345300 by mananth(16946)\"\" \"About 
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Investment I 6.50% per annum ---x
\n" ); document.write( "Investment II 7.50% per annum ---y
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\n" ); document.write( "x + y= 25000 ------------------------1
\n" ); document.write( "6.50% x + 7.50% y= = $1,785.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6.5 x + 7.5 y= = $178,500.00 --------2
\n" ); document.write( "
\n" ); document.write( "Multiply (1) by -6.5
\n" ); document.write( "we get
\n" ); document.write( "
\n" ); document.write( "-6.5 x -6.5 y= = -162500.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "y=$16,000.00 investment at 7.50%
\n" ); document.write( "Balance $9,000.00 investment at 6.50%
\n" ); document.write( "CHECK
\n" ); document.write( "$9,000.00 --------- 6.50% ------- $585.00
\n" ); document.write( "$16,000.00 ------- 7.50% ------- $1,200.00
\n" ); document.write( "Total -------------- $1,785.00
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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