document.write( "Question 518852: Janey is twice as old as Peter. The sum of their ages is 5 times Peter's age less 48. How old are Peter and Janey? Can you help me with writing an equation to solve the equation and work out their ages please.
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Algebra.Com's Answer #345293 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Janey = j \n" ); document.write( "Present age of Peter = p\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Janey is twice as old as Peter. \n" ); document.write( "j=2p.........(1) \n" ); document.write( "The sum of their ages is 5 times Peter's age less 48. \n" ); document.write( "j+p=5p-48 \n" ); document.write( "j=5p-48-p \n" ); document.write( "j=4p-48.........(2) \n" ); document.write( "Put the value of j from (1) to (2) \n" ); document.write( "2p=4p-48 \n" ); document.write( "2p-4p=-48 \n" ); document.write( "-2p=-48 \n" ); document.write( "-2p/-2=-48/-2 \n" ); document.write( "p=24 \n" ); document.write( "Put the value of p in (1) \n" ); document.write( "j=2p \n" ); document.write( "j=2*24 \n" ); document.write( "j=48\r \n" ); document.write( "\n" ); document.write( "Present age of Janey = j = 48 years old \n" ); document.write( "Present age of Peter = p = 24 years old \n" ); document.write( " \n" ); document.write( " |