document.write( "Question 518887: Mary is twice as old as Jamie. Together their age add up to 54. How old is each of them? \n" ); document.write( "
Algebra.Com's Answer #345292 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Mary = m \n" ); document.write( "Present age of Jamie = j\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mary is twice as old as Jamie. \n" ); document.write( "m=2j........(1) \n" ); document.write( "Together their age add up to 54. \n" ); document.write( "m+j=54 \n" ); document.write( "Put the value of m in above equation \n" ); document.write( "2j+j=54 \n" ); document.write( "3j=54 \n" ); document.write( "3j/3=54/3 \n" ); document.write( "j=18 \n" ); document.write( "Put the value of j in (1) \n" ); document.write( "m=2(18) \n" ); document.write( "m=36 \n" ); document.write( "Present age of Mary = m = 36 years old \n" ); document.write( "Present age of Jamie = j = 18 years old \n" ); document.write( " \n" ); document.write( " |