document.write( "Question 518887: Mary is twice as old as Jamie. Together their age add up to 54. How old is each of them? \n" ); document.write( "
Algebra.Com's Answer #345292 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "Present age of Mary = m
\n" ); document.write( "Present age of Jamie = j\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mary is twice as old as Jamie.
\n" ); document.write( "m=2j........(1)
\n" ); document.write( "Together their age add up to 54.
\n" ); document.write( "m+j=54
\n" ); document.write( "Put the value of m in above equation
\n" ); document.write( "2j+j=54
\n" ); document.write( "3j=54
\n" ); document.write( "3j/3=54/3
\n" ); document.write( "j=18
\n" ); document.write( "Put the value of j in (1)
\n" ); document.write( "m=2(18)
\n" ); document.write( "m=36
\n" ); document.write( "Present age of Mary = m = 36 years old
\n" ); document.write( "Present age of Jamie = j = 18 years old
\n" ); document.write( "
\n" ); document.write( "
\n" );