document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=518914>Question 518914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i jerry is traveling to sues house. he needs to know how far away she lives from him. if jerry lives at(8,4) and sue lives at(-5,-3, how far is sues house from jerry. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345289 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the formula for Distance between two points:-<BR>\n" );
document.write( "d=sqrt((x1-x2)^2+(y1+y2)^2)<BR>\n" );
document.write( "Pints (8,4),(-5,-3)<BR>\n" );
document.write( "d=sqrt((8-(-5))^2+(4-(-3))^2)<BR>\n" );
document.write( "d=sqrt((8+5))^2+(4+3)^2)<BR>\n" );
document.write( "d=sqrt((13)^2+(7)^2)<BR>\n" );
document.write( "d=sqrt(169+49)<BR>\n" );
document.write( "d=sqrt(218)<BR>\n" );
document.write( "d=14.76\r<BR>\n" );
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