document.write( "Question 517794: find the vertex x and y intercept of the parabola given by the equation y=3x^2-2x+1 \n" ); document.write( "
Algebra.Com's Answer #345287 by lwsshak3(11628)\"\" \"About 
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find the vertex x and y intercept of the parabola given by the equation y=3x^2-2x+1
\n" ); document.write( "**
\n" ); document.write( "y=3x^2-2x+1
\n" ); document.write( "y-intercept
\n" ); document.write( "set x=0
\n" ); document.write( "y=0-0+1=1
\n" ); document.write( "y-intercept=1
\n" ); document.write( "..
\n" ); document.write( "y=3x^2-2x+1
\n" ); document.write( "complete the square
\n" ); document.write( "y=3(x^2-2x/3+1/9)+1-1/3
\n" ); document.write( "y=3(x-1/3)^2+2/3
\n" ); document.write( "vertex: (1/3,2/3)
\n" ); document.write( "..
\n" ); document.write( "Since the minimum point on the curve is 2/3, there is no crossing of the x-axis, thus, there are no x-intercepts \n" ); document.write( "
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