document.write( "Question 518890: Lee can walk 8 miles in the same time it takes Sabrina to walk 6 miles. If Lee walks 1 mile per hour faster than Sabrina, then how fast does each of them walk?
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Algebra.Com's Answer #345284 by Sohail Ahmed Khan(1)![]() ![]() ![]() You can put this solution on YOUR website! This would be my first solution here, so I may not be using the available tools fully.Any how:\r \n" ); document.write( "\n" ); document.write( "LEE: covers 8 miles in T hours, this implies that his speed is: (8/T)miles/hour.\r \n" ); document.write( "\n" ); document.write( "Sabrina: Covers 6 miles in T hours, this implies that her speed is: (6/T) miles/hour.\r \n" ); document.write( "\n" ); document.write( "Now It is already told to us that the LEE speed is greater than Sabrina's speed by 1 miles/hour.\r \n" ); document.write( "\n" ); document.write( "SO from above we get:\r \n" ); document.write( "\n" ); document.write( "LEE Speed = Sabrina Speed + 1 \n" ); document.write( "8/T = 6/T +1\r \n" ); document.write( "\n" ); document.write( "Solving for T gives T=2. \n" ); document.write( "Hence LEE's speed is 4 miles/hour and Sabrina speed is 3 miles/hour.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |