document.write( "Question 518831: what are the vertex, y-intercept, and x intercepts for -(2x-3)(x+2) \n" ); document.write( "
Algebra.Com's Answer #345283 by lwsshak3(11628)\"\" \"About 
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what are the vertex, y-intercept, and x intercepts for -(2x-3)(x+2)
\n" ); document.write( "**
\n" ); document.write( "y=-(2x-3)(x+2)
\n" ); document.write( "y=(-2x+3)(x+2)=0
\n" ); document.write( "x-intercepts
\n" ); document.write( "-2x+3=0
\n" ); document.write( "2x=3
\n" ); document.write( "x=3/2
\n" ); document.write( "or
\n" ); document.write( "x+2=0
\n" ); document.write( "x=-2
\n" ); document.write( "..
\n" ); document.write( "y-intercepts
\n" ); document.write( "x=0
\n" ); document.write( "y=-(2x-3)(x+2)=6
\n" ); document.write( "..
\n" ); document.write( "Vertex
\n" ); document.write( "y=-(2x^2+x-6)=-2x^2-x+6
\n" ); document.write( "complete the square
\n" ); document.write( "y=-2(x^2+x/2+1/16)+6+1/8
\n" ); document.write( "y=-2(x+1/4)^2+49/8
\n" ); document.write( "vertex:(-1/4,49/8)
\n" ); document.write( "ans:
\n" ); document.write( "x-intercepts: 3/2 and -2
\n" ); document.write( "y-intercept=6
\n" ); document.write( "vertex:(-1/4,49/8) \n" ); document.write( "
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