document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=518652>Question 518652</A>: <I><SPAN STYLE=\"word-break: break-all;\"> surface Area and volume of spheres, cones and cylinders\r<BR>\n" );
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document.write( "16. The diameter of a volleyball is 10.9cm <BR>\n" );
document.write( "a) Determine the amount of leather needed to make the ball\r<BR>\n" );
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document.write( "b)Determine the amount of air inside the ball<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345234 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of a volleyball is 10.9cm <BR>\n" );
document.write( "a) Determine the amount of leather needed to make the ball<BR>\n" );
document.write( "Area = 4(pi)r^2<BR>\n" );
document.write( "Area = 4(pi)(5.45)^2 = 373.25 sq cm.<BR>\n" );
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document.write( "b)Determine the amount of air inside the ball<BR>\n" );
document.write( "Volume = (4/3)(pi)r^3<BR>\n" );
document.write( "Volume = (4/3)(pi)(5.45)^3 = 678.08 cm^3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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