document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=518202>Question 518202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits is 12.<BR>\n" );
document.write( "The digit in the tousandths place is 3 times the digit in the tens place.<BR>\n" );
document.write( "To the nearest ten, the number rounds to 30.<BR>\n" );
document.write( "The digit in the tenths place is one more than the digit in the hundredths place.<BR>\n" );
document.write( "What is the number?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345173 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The three digits: a, b, c, d<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"The sum of the digits is 12.\"<BR>\n" );
document.write( "a + b + c + d = 12<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"The digit in the thousandths place is 3 times the digit in the tens place.\"<BR>\n" );
document.write( "a = 3c<BR>\n" );
document.write( "\"The digit in the tenths place is one more than the digit in the hundredths place.\"<BR>\n" );
document.write( "c = b + 1<BR>\n" );
document.write( "or<BR>\n" );
document.write( "b = (c-1) <BR>\n" );
document.write( ":<BR>\n" );
document.write( "a + b + c + d = 12<BR>\n" );
document.write( "Replace a and b<BR>\n" );
document.write( "3c + (c-1) + c + d = 12<BR>\n" );
document.write( "5c + d = 12 + 1<BR>\n" );
document.write( "5c + d = 13<BR>\n" );
document.write( "Assume that c has to equal 2, therefore<BR>\n" );
document.write( "5(2) + d = 13<BR>\n" );
document.write( "10 + d = 13<BR>\n" );
document.write( "d = 13 - 10<BR>\n" );
document.write( "d = 3<BR>\n" );
document.write( "find the rest of the digits<BR>\n" );
document.write( "a = 3(2) = 6<BR>\n" );
document.write( "b = 2-1 = 1<BR>\n" );
document.write( "c = 2<BR>\n" );
document.write( "d = 3<BR>\n" );
document.write( "then<BR>\n" );
document.write( "6123 is the number<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Assume that c has to equal 1, therefore<BR>\n" );
document.write( "5(1) + d = 13<BR>\n" );
document.write( "5 + d = 13<BR>\n" );
document.write( "d = 13 - 5<BR>\n" );
document.write( "d = 8<BR>\n" );
document.write( "find the rest of the digits<BR>\n" );
document.write( "a = 3(1) = 3<BR>\n" );
document.write( "b = 1-1 = 0<BR>\n" );
document.write( "c = 1<BR>\n" );
document.write( "d = 8<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3018 is the number<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"To the nearest ten, the number rounds to 30.\" Not sure what bearing this has on this problem. </SPAN>\n" );
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