document.write( "Question 518403: Leonard's sister Theresa was 8 years older than twice his age 3 years ago. Now Theresa is one year less than three times Leonard's age.\r
\n" ); document.write( "\n" ); document.write( "How old is Leonard now? \n" ); document.write( "
Algebra.Com's Answer #345161 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Leonard = d
\n" ); document.write( "Present age of Theresa = t\r
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\n" ); document.write( "\n" ); document.write( "Now Theresa is one year less than three times Leonard's age.
\n" ); document.write( "t=3d-1...............(1)
\n" ); document.write( "Three years ago
\n" ); document.write( "Leonard was = d-3
\n" ); document.write( "Theresa = t-3
\n" ); document.write( "Then
\n" ); document.write( "Theresa was 8 years older than twice Leonard
\n" ); document.write( "t-3=2(d-3)+8
\n" ); document.write( "t-3=2d-6+8
\n" ); document.write( "t-3=2d+2
\n" ); document.write( "t=2d+2+3
\n" ); document.write( "t=2d+5...............(2)
\n" ); document.write( "Put the value of t from (1) to (2)
\n" ); document.write( "3d-1=2d+5
\n" ); document.write( "3d-2d=5+1
\n" ); document.write( "d=6
\n" ); document.write( "Put the value of d in (1)
\n" ); document.write( "t=3d-1
\n" ); document.write( "t=3(6)-1
\n" ); document.write( "t=18-1
\n" ); document.write( "t=17
\n" ); document.write( "Present age of Leonard = d = 6 years old
\n" ); document.write( "Present age of Theresa = t = 17 years old
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