document.write( "Question 518142: cassandra has a total of 53 dimes and quarters. the dimes have a value of $6.60 less than the quarters. how much money does she have \n" ); document.write( "
Algebra.Com's Answer #345141 by ankor@dixie-net.com(22740)\"\" \"About 
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Let d = no. of dimes
\n" ); document.write( "Let q = no. of quarters
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"Cassandra has a total of 53 dimes and quarters.\"
\n" ); document.write( "d + q = 53
\n" ); document.write( "d = (53-q); use this for substitution
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\n" ); document.write( "\"the dimes have a value of $6.60 less than the quarters.\"
\n" ); document.write( ".25q - .10d = 6.60
\n" ); document.write( "replace d with (53-q)
\n" ); document.write( ".25q - .10(53-q) = 6.60
\n" ); document.write( ".25q - 5.30 + .10q = 6.60
\n" ); document.write( ".25q + .10q = 6.60 + 5.30
\n" ); document.write( ".35q = 11.90
\n" ); document.write( "q = 11.9/.35
\n" ); document.write( "q = 34 quarters
\n" ); document.write( "then
\n" ); document.write( "53 - 34 = 10 dimes
\n" ); document.write( "Find the total value
\n" ); document.write( ".25(34) + .10(19) = $10.40
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\n" ); document.write( "You can confirm these solutions: .25(34) - .10(19) = 6.60\r
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