document.write( "Question 518308: A man is now 40 years old and his son is 14 years old. A number of years from now, the father will be twice as old as his son. What is this number of years? \n" ); document.write( "
Algebra.Com's Answer #345121 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Man's age = 40 \n" ); document.write( "Sons's age = 14\r \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( "Number of years = x \n" ); document.write( "father will be = 40 + x \n" ); document.write( "Son will be = 14 + x\r \n" ); document.write( "\n" ); document.write( "Twice the age of son after x years = father's age after x years \n" ); document.write( "2(14+x)=40+x \n" ); document.write( "28+2x=40+x \n" ); document.write( "2x-x=40-28 \n" ); document.write( "x=12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "After 12 years father will be twice as old as his son.\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "====== \n" ); document.write( "Man's age = 40 +12 = 52 (which is twice of 26) \n" ); document.write( "Sons's age = 14 + 12 = 26 \n" ); document.write( " |