document.write( "Question 518308: A man is now 40 years old and his son is 14 years old. A number of years from now, the father will be twice as old as his son. What is this number of years? \n" ); document.write( "
Algebra.Com's Answer #345121 by Maths68(1474)\"\" \"About 
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Man's age = 40
\n" ); document.write( "Sons's age = 14\r
\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "Number of years = x
\n" ); document.write( "father will be = 40 + x
\n" ); document.write( "Son will be = 14 + x\r
\n" ); document.write( "\n" ); document.write( "Twice the age of son after x years = father's age after x years
\n" ); document.write( "2(14+x)=40+x
\n" ); document.write( "28+2x=40+x
\n" ); document.write( "2x-x=40-28
\n" ); document.write( "x=12\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "After 12 years father will be twice as old as his son.\r
\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "Man's age = 40 +12 = 52 (which is twice of 26)
\n" ); document.write( "Sons's age = 14 + 12 = 26
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