document.write( "Question 518179: My word problem is:
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document.write( "A car and a motor cycle leave a rest area at the same time, with the car traveling 8 mph faster than the motorcycle. The car then travels 105 mi in the time it takes the motorcycle to travel 93 mi. Find the speed of each vehicle. \n" );
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Algebra.Com's Answer #345084 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! d = r*t is the basic distance equation \n" ); document.write( ". \n" ); document.write( "Car: \n" ); document.write( "d = 105 miles \n" ); document.write( "r = speed of motorcycle +8 = s+8 \n" ); document.write( "t = same as motorcycle = d/r = 105/(s+8) \n" ); document.write( ". \n" ); document.write( "Motorcycle: \n" ); document.write( "d = 93 miles \n" ); document.write( "r = speed of motorcycle = s \n" ); document.write( "t = same as the car = d/r = 93/s \n" ); document.write( ". \n" ); document.write( "t = t \n" ); document.write( "so \n" ); document.write( "105/(s+8) = 93/s \n" ); document.write( ". \n" ); document.write( "cross multiply \n" ); document.write( ". \n" ); document.write( "105*s = (s+8)*93 \n" ); document.write( ". \n" ); document.write( "105s = 93s + 744 \n" ); document.write( ". \n" ); document.write( "12s = 744 \n" ); document.write( ". \n" ); document.write( "s = 62 mph = motorcyle's speed \n" ); document.write( ". \n" ); document.write( "s + 8 = 70 mph = car's speed \n" ); document.write( ". \n" ); document.write( "Check the answer: \n" ); document.write( "How long does it take the car to travel 105 miles? \n" ); document.write( "105/70 = 3/2 \n" ); document.write( "How long does it take the motorcycle to travel 93 miles? \n" ); document.write( "93/62 = 3/2 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |