document.write( "Question 518110: Kathy is 6yrs older than her cat. Next year she will be twice as old as her cat will be. How old is her cat now? \n" ); document.write( "
Algebra.Com's Answer #345039 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Kathy's age = K \n" ); document.write( "Cat's age = C \n" ); document.write( ". \n" ); document.write( "K = C +6 \n" ); document.write( ". \n" ); document.write( "Next year... \n" ); document.write( "K+1 \n" ); document.write( "C+1 \n" ); document.write( "K+1 = 2(C+1) \n" ); document.write( ". \n" ); document.write( "Substitute K =C+6 \n" ); document.write( ". \n" ); document.write( "C+6 +1 = 2(C+1) \n" ); document.write( "C+7 = 2C +2 \n" ); document.write( "-C = -5 \n" ); document.write( "C = 5 \n" ); document.write( ". \n" ); document.write( "The cat is 5 years old. \n" ); document.write( "so \n" ); document.write( "Kathy is 11 years old (5+6=11). \n" ); document.write( ". \n" ); document.write( "Next year, Kathy will be 12 and the cat will be 6, so Kathy will be twice the cat's age. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |