document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=518014>Question 518014</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem:\r<BR>\n" );
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document.write( "(4i)/(3+i)\r<BR>\n" );
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document.write( "So far, I've got:\r<BR>\n" );
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document.write( "[(4i)/(3+i)] * (3-i) = (12i-4i^2)/(9-i^2)\r<BR>\n" );
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document.write( "I know that having i^2 = -1 but I was wondering if since it's already -4i^2 does that make it +4 or does it stay -4?\r<BR>\n" );
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document.write( "Thanks for your help. It is much appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #345016 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=345016\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4i)/(3+i) <BR>\n" );
document.write( "So far, I've got: <BR>\n" );
document.write( "[(4i)/(3+i)] * (3-i) = (12i-4i^2)/(9-i^2) <BR>\n" );
document.write( "I know that having i^2 = -1 but I was wondering if since it's already -4i^2 does that make it +4 or does it stay -4? <BR>\n" );
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document.write( "-4*-1 = +4<BR>\n" );
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document.write( "[(4i)/(3+i)] * (3-i)/(3-i) = (12i-4i^2)/(9-i^2) right so far<BR>\n" );
document.write( "= (4 + 12i)/10<BR>\n" );
document.write( "= (2 + 6i)/5<BR>\n" );
document.write( " </SPAN>\n" );
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