document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=517994>Question 517994</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What amounts of each should be used?\r<BR>\n" );
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document.write( "How many liters of 100% pure acid should be used to make the solution?\r<BR>\n" );
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document.write( "How many liters of the 10% solution should be used in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344997 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 10% acid solution to obtain 90L of 60% solution. What amounts of each should be used? <BR>\n" );
document.write( "How many liters of 100% pure acid should be used to make the solution?<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "1.00x + 0.10(90-x) = 0.6*90<BR>\n" );
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document.write( "100x + 10*90 - 10x = 60*90<BR>\n" );
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document.write( "90x = 50*90<BR>\n" );
document.write( "x = 50 L (amt. of pure acid needed)<BR>\n" );
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document.write( "How many liters of the 10% solution should be used in the mixture?<BR>\n" );
document.write( "90-x = 90-50 = 40L (amt of 10% solution needed.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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