document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=517951>Question 517951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a rectangular table with an area of 35sq ft has a width  that is 2 ft less than the length what are the dimensions of the table.  \r<BR>\n" );
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document.write( "I think it is written\r<BR>\n" );
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document.write( "2(l x l-2)=35  let me know if I doing this right and I need help with steps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344983 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=X<BR>\n" );
document.write( "W=X-2<BR>\n" );
document.write( "AREA=LW<BR>\n" );
document.write( "35=X(X-2)<BR>\n" );
document.write( "35=X^2-2X<BR>\n" );
document.write( "X^2-2X-35=0<BR>\n" );
document.write( "(X-7)(X+5)=0<BR>\n" );
document.write( "X-7=0<BR>\n" );
document.write( "X=7 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "7-2=5 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "35=7(7-5)<BR>\n" );
document.write( "35=7*5<BR>\n" );
document.write( "35=35 </SPAN>\n" );
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