document.write( "Question 517975: if one car goes thirty miles per hour, and another goes 60 miles per hour but leaves two hours later, when will the meet up \n" ); document.write( "
Algebra.Com's Answer #344979 by stanbon(75887)\"\" \"About 
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if one car goes thirty miles per hour, and another goes 60 miles per hour but leaves two hours later, when will the meet up
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\n" ); document.write( "slower car DATA:
\n" ); document.write( "rate = 30 mph ; time = x hrs ; distance = rt = 30x miles
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\n" ); document.write( "faster car DATA:
\n" ); document.write( "rate = 60 mph ; time = x-2 hrs; distance = rt = 60(x-2) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "30x = 60(x-2)
\n" ); document.write( "30x = 60x - 60*2
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\n" ); document.write( "30x = 60*2
\n" ); document.write( "x = 4 hrs (time for faster to catch up to slower)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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