document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=517957>Question 517957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find four consecutive intergers such that twice the first subtracted from the sum of the other three intergers is 16. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344976 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+1, X+2, & X+3 be the 4 integers.<BR>\n" );
document.write( "(X+1)+(X+2)+(X+3)-2X=16<BR>\n" );
document.write( "3X+6-2X=16<BR>\n" );
document.write( "X+6=16<BR>\n" );
document.write( "X=16-6<BR>\n" );
document.write( "X=10 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "(10+1)+(10+2)+(10+3)-2*10=16<BR>\n" );
document.write( "11+12+13-20=16<BR>\n" );
document.write( "36-20=16<BR>\n" );
document.write( "16=16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );