document.write( "Question 517849: What are the remaining trigonometric functions of theta when sin theta= square root 3/2, cos theta < 0. \n" ); document.write( "
Algebra.Com's Answer #344968 by lwsshak3(11628)\"\" \"About 
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What are the remaining trigonometric functions of theta when sin theta= square root 3/2, cos theta < 0
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\n" ); document.write( "When sin x =√2/3, and cos<0, it means the reference angle is in quadrant II, where sin>0 and cos<0. You are working with a right triangle where the opposite side=√2 and the hypotenuse=3. Using the Pythagorean Theorem, adjacent side =√[(3^2)-(√2)^2]=√(9-2)=√7
\n" ); document.write( "Trig functions:
\n" ); document.write( "sin x = √2/3 (given)
\n" ); document.write( "cos x = √7/3
\n" ); document.write( "tan x = √2/√7=√14/7
\n" ); document.write( "csc x =3/√2=3√2/2
\n" ); document.write( "sec x =3/√7=3√7/7
\n" ); document.write( "cot x =√7/√2=√14/2 \n" ); document.write( "
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