document.write( "Question 517795: A ball is thrown straight up with an initial velocity of 80 feet per second from the top of a building 23 feet tall. It's height h (in feet) above the ground t seconds after the ball is thrown is given by h = -16t^2 + 80t + 23. When will the ball be 119 feet above the ground for the first time?\r
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document.write( "*** ^2 stands for squared or to the second power *** \n" );
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Algebra.Com's Answer #344937 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The ball will probably be 119' above the ground twice: \n" ); document.write( "once going up and again coming down. \n" ); document.write( "Just pick the smallest value for \n" ); document.write( "be going up. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Use quadratic formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, also, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2 sec from when the ball is thrown, the \n" ); document.write( "height will be 119' above ground for the first time. \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( "Here's a plot: \n" ); document.write( " |