document.write( "Question 517775: a Tour bus leaves Sacramento every Friday evening at 5 pm for a 170 mile trip. this week however the bus leaves at 5:30 pm. to arrive on time , the driver drives 9 miles per hour faster than usual what is the buses usual speed? please show work \n" ); document.write( "
Algebra.Com's Answer #344926 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let represent the usual speed. Let represent the usual amount of time. Then represents the increased speed and represents the reduced time.\r
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\n" ); document.write( "\n" ); document.write( "Time is equal to distance divided by rate so for the normal trip:\r
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\n" ); document.write( "\n" ); document.write( "And for the 'catch-up' trip:\r
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\n" ); document.write( "\n" ); document.write( "Which is to say:\r
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\n" ); document.write( "\n" ); document.write( "A little Algebra Music, Maestro:\r
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\n" ); document.write( "\n" ); document.write( "Now that we have two expression that are each equal to , set them equal:\r
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\n" ); document.write( "\n" ); document.write( "All that is left is to cross multiply, collect terms, and solve for \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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